#584. NOIP2012TG-23
NOIP2012TG-23
- (阅读程序写结果)
#include<iostream>
using namespace std;
int n,i,temp,sum,a[100];
int main()
{
cin>>n;
for(i=1;i<=n;i++)
cin>>a[i];
for(i=1;i<=n-1;i++)
if(a[i]>a[i+1]){
temp=a[i];
a[i]=a[i+1];
a[i+1]=temp;
}
for(i=n;i>=2;i--)
if(a[i]<a[i-1]){
temp=a[i];
a[i]=a[i-1];
a[i-1]=temp;
}
sum=0;
for(i=2;i<=n-1;i++)
sum+=a[i];
cout<<sum/(n-2)<<endl;
return 0;
}
输入:
8
40 70 50 70 20 40 10 30
输出:{{ input(1) }}