#471. NOIP2008TG-23

NOIP2008TG-23

  1. (阅读程序写结果)
#include<stdio.h>
int main()
{
	int i, a, b, c, d, f[4];
	for(i = 0; i < 4; i++)
		scanf("%d", &f[i]);

	a = f[0] + f[1] + f[2] + f[3];
	a = a / f[0];
	b = f[0] + f[2] + f[3];
	b = b / a;
	c = (b * f[1] + a) / f[2];
	d = f[(b / c ) % 4];
	if(f[(a + b + c + d) % 4] > f[2])
		printf("%d\n", a + b);
	else
		printf("%d\n", c + d);
	return 0;
}

输入:9 19 29 39

输出:{{ input(1) }}